6th Maths - Term 1 Exam 2024-25 | Solved Paper
This post contains the complete solutions for the First Term Summative Assessment (SA) 2024-25 for Class 6 Mathematics, held in the Chennai district. Students can use this to verify their answers and understand the problem-solving methods for each question.
PART - I
I. Choose the correct Answer. (5 x 1 = 5)
1. The value of 24 ÷ {8 - (3 x 2)} is _______
Calculation: 24 ÷ {8 - 6} = 24 ÷ 2 = 12
a) 0 b) 12 c) 3 d) 4
Answer: b) 12
2. The value of 'y' in y + 7 = 13 is _______
Calculation: y = 13 - 7 = 6
a) y = 5 b) y = 6 c) y = 7 d) y = 8
Answer: b) y = 6
3. If 2 : 3 = 4 : x, Then the value of x is _______
Calculation: \(\frac{2}{3} = \frac{4}{x} \implies 2x = 4 \times 3 \implies 2x = 12 \implies x = 6\)
a) 6 b) 2 c) 4 d) 3
Answer: a) 6
4. An angle between more than 180° to less than 360° is called _______
a) Acute angle b) Obtuse angle c) Straight angle d) Reflex angle
Answer: d) Reflex angle
5. The representation of 'One picture to many objects' in a pictograph is called _______
a) Tally mark b) Pictoword c) Scaling d) Frequency
Answer: c) Scaling
II. Fill in the blanks (5 x 1 = 5)
6. The nearest thousand (1000) of 756 is _______
7. If A's age is 'n' years now, 7 years ago A's age was _______
8. Ratio of 3m to 200 cm = _______
First, convert to the same unit: 3 m = 300 cm.
The ratio is 300 cm : 200 cm.
Simplifying by dividing by 100 gives 3 : 2.
Answer: 3 : 2
9. A ray has _______ end point(s).
10. Representation of data by using pictures is known as _______
III. Say True or False: (5 x 1 = 5)
11. 139 is rounded off as 100 to the nearest 100.
12. 10 more to three times 'C' is '10C + 3'.
13. One of the terms in a ratio cannot be 1.
14. 0° and 180° are supplementary.
15. The collected information is called Data.
IV. Match the following. (5 x 1 = 5)
| Question | Column A | Column B |
|---|---|---|
| 16. | (53+49) x 0 | 0 |
| 17. | If 2m = 10 then value of m | 5 |
| 18. | Value of 12 : 12 in fraction | 1 |
| 19. | No. of. end points in the line segment | 2 |
| 20. | Tally mark |||| represents the No. | 4 |
Correct Matches:
- 16. (53+49) x 0 → 0
- 17. If 2m = 10 then value of m → 5
- 18. Value of 12 : 12 in fraction (12/12) → 1
- 19. No. of end points in the line segment → 2
- 20. Tally mark |||| represents the No. → 4
PART - II
IV. Answer any 10 of the following. Q.No.34 is compulsory. (10 x 2 = 20)
21. Of the numbers 1386787215, 137698890, 86720560, Which one is the largest? Which one is the smallest.
- The number with the most digits is the largest. 1386787215 has 10 digits.
- The number with the fewest digits is the smallest. 86720560 has 8 digits.
Largest: 1386787215
Smallest: 86720560
22. Simplify: 24 ÷ 2 x 8 + 2 - 1.
Using BODMAS/PEMDAS rule (Division and Multiplication have same priority, so we go from left to right):
24 ÷ 2 x 8 + 2 - 1
= 12 x 8 + 2 - 1
= 96 + 2 - 1
= 98 - 1
= 97
23. Estimate by rounding off each number to the nearest hundred. 8074 + 4178.
- 8074 rounded to the nearest hundred is 8100 (since 74 > 50).
- 4178 rounded to the nearest hundred is 4200 (since 78 > 50).
Estimated Sum = 8100 + 4200 = 12300
24. What is the value of 'S', if '2S-6' gives 30?
2S - 6 = 30
2S = 30 + 6
2S = 36
S = 36 / 2
S = 18
25. A piece of wire is '12S' cm long. What will be the length of the side of an Equilateral Triangle formed from it.
Perimeter of the equilateral triangle = Length of the wire = 12S cm.
An equilateral triangle has 3 equal sides.
Length of one side = Perimeter / 3 = 12S / 3 = 4S cm.
26. Find the ratio of 500g to 250g.
Ratio = 500 : 250
Divide both sides by the greatest common divisor, which is 250.
(500/250) : (250/250) = 2 : 1
Answer: 2 : 1
27. Give two equivalent ratios for 3 : 2.
To find equivalent ratios, multiply both terms by the same non-zero number.
- Multiply by 2: (3 x 2) : (2 x 2) = 6 : 4
- Multiply by 3: (3 x 3) : (2 x 3) = 9 : 6
28. Find the number of line segments in the given figure and represent its name also.
The figure shows three collinear points A, B, C.
The line segments are:
- AB
- BC
- AC
Total number of line segments = 3.
29. Find the Complementary angle of i) 30° ii) 85°
Complementary angles add up to 90°.
- i) Complement of 30° = 90° - 30° = 60°
- ii) Complement of 85° = 90° - 85° = 5°
30. Draw any 3 lines to have a point of concurrency.
To show a point of concurrency, draw three or more straight lines that all intersect at a single common point. This point is called the point of concurrency.
31. Write the types of Data.
The two main types of data are:
- Primary Data: Information collected directly by the investigator for a specific purpose.
- Secondary Data: Information that has already been collected by someone else and is available from other sources.
32. Suppose, you have two shorts, one is black and the other one is blue, three shirts which are in white, blue and red. You again wish to make different combinations but you always want to make sure that the shorts and shirt that you wear are of different colours. List and Check how many combinations are possible now.
Shorts = {Black, Blue}, Shirts = {White, Blue, Red}
Combinations with Black Shorts:
1. Black Shorts + White Shirt
2. Black Shorts + Blue Shirt
3. Black Shorts + Red Shirt
Combinations with Blue Shorts (shirt must be a different color):
4. Blue Shorts + White Shirt
5. Blue Shorts + Red Shirt
(Cannot pair Blue Shorts with Blue Shirt)
Total possible combinations = 3 + 2 = 5.
33. Name the Vertex and Sides of the angles.
From the given angle ∠EDF:
- Vertex: The common point where the two rays meet is D.
- Sides: The two rays that form the angle are Ray ED and Ray DF.
34. (Compulsory) How many triangles are there in the given figures?
The figure shows a large triangle with its interior divided by connecting the midpoints of its sides. This creates 4 smaller triangles inside and 1 large outer triangle.
- The top small triangle.
- The bottom-left small triangle.
- The bottom-right small triangle.
- The central inverted small triangle.
- The large outer triangle itself.
Total number of triangles = 5.
PART - III
V. Answer any five of the following questions. (5 x 3 = 15)
35. Tamilnadu has about twenty six thousand three hundred forty five square kilometre of forest land. Write the number mentioned in the statement in Indian System.
Twenty six thousand = 26,000
Three hundred forty five = 345
The number is 26,000 + 345 = 26345.
In the Indian System, this is written as 26,345.
36. In a Cycle factory, 1560 bicycles were manufactured everyday. Find the number of bicycles manufactured in 25 days.
Bicycles manufactured per day = 1560
Number of days = 25
Total bicycles manufactured = 1560 x 25
= 1560 x (100 / 4) = 156000 / 4 = 39000
Answer: 39,000 bicycles.
37. Name the property being illustrated in each of the cases given below.
i) 75 + 34 = 34 + 75
ii) 5 + 0 = 5
iii) 50 x 1 = 50
- i) Commutative property of addition (The order of numbers can be changed without affecting the sum).
- ii) Additive Identity (Adding zero to a number does not change the number).
- iii) Multiplicative Identity (Multiplying a number by one does not change the number).
38. If g is equal to 300 what is the value of g - 1 and 'g+1'?
Given g = 300
- g - 1 = 300 - 1 = 299
- g + 1 = 300 + 1 = 301
39. A piece of wire is '12S' cm long. What will be the length of the side, If it is formed as
i) An equilateral Triangle
ii) A Square
Total length of wire (Perimeter) = 12S cm
- i) Equilateral Triangle: It has 3 equal sides.
Length of one side = Perimeter / 3 = 12S / 3 = 4S cm. - ii) A Square: It has 4 equal sides.
Length of one side = Perimeter / 4 = 12S / 4 = 3S cm.
40. If a person reads 20 pages of a book in 2 hours, How many pages will be read in 8 hours at the same speed?
Method 1: Unitary Method
Pages read in 2 hours = 20
Pages read in 1 hour = 20 / 2 = 10 pages.
Pages read in 8 hours = 10 x 8 = 80 pages.
Method 2: Ratio and Proportion
Let x be the number of pages read in 8 hours.
20 pages : 2 hours = x pages : 8 hours
\(\frac{20}{2} = \frac{x}{8} \implies 10 = \frac{x}{8} \implies x = 10 \times 8 = 80\)
Answer: 80 pages.
41. From the given figure, Name the
i) Parallel lines
ii) Intersecting lines
iii) Point of intersection
Based on the provided diagram:
- i) Parallel lines: Lines that do not intersect. The pairs are (l1, l2) and (EF, GH).
- ii) Intersecting lines: Lines that cross each other. The pairs are (AB, CD), (l1, l3), (l2, l3), etc.
- iii) Point of intersection: The point where lines cross. For example, point I is the intersection of AB and CD. Point P is the intersection of l1 and l3.
42. Name the following angle names
i) 0° ii) 89° iii) 245° iv) 90° v) 180° vi) 135°
- i) 0° → Zero Angle
- ii) 89° → Acute Angle (less than 90°)
- iii) 245° → Reflex Angle (between 180° and 360°)
- iv) 90° → Right Angle
- v) 180° → Straight Angle
- vi) 135° → Obtuse Angle (between 90° and 180°)
PART - IV
VI. Answer any One of the following. (1 x 5 = 5)
43. a) With the help of Ruler and Compass, Draw a line segment AB = 7.5 cm.
Steps to construct AB = 7.5 cm:
1. Draw a line and mark a point 'A' on it.
2. Place the metal tip of the compass on the '0' mark of the ruler.
3. Extend the pencil tip of the compass to the 7.5 cm mark.
4. Without changing the compass width, place the metal tip on 'A' and draw a small arc to cut the line.
5. Mark the point of intersection as 'B'.
6. AB is the required line segment of length 7.5 cm.
43. (OR) b) Use a protractor to draw an angle 90°.
Steps of Construction:
- Draw a ray and name it OA. This will be one side of the angle.
- Place the center point of the protractor on the vertex O.
- Align the baseline of the protractor with the ray OA.
- Find the 90° mark on the protractor's scale and mark a small dot. Name this point B.
- Remove the protractor.
- With a ruler, draw a ray from the vertex O through the point B.
- The resulting angle, ∠AOB, is the required 90° angle.
